Question

if x³+1=0
x≠-1
find
${x}^{1 } + {x}^{2} ................ {x}^{2020}$


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Answer 1

Answer:

2020

Step-by-step explanation:

if x³=1

then x=³√1

x=±1 and x≠-1

then x=1

so

x¹+x²+x³+x⁴+........................x^2020

1¹+1²+1³+1⁴+.............................1^2020

=1+1+1+1+1+1+1+.............1+1+1.(2020 times)

=2020

Hope it works..................................™✌️