if x3 + 1/x 3 = 10, than x+1/x=
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▪︎ (x+x1)3=(x3+x31)+3(x+x1)
⇒ (x+x1)3=110+3(x+x1)
Let y=x+x1
⇒ y3=110+3y
⇒ y3−3y−110=0
⇒ y3−5y2+5y2−3y−110=0
⇒ y2(y−5)+5y2−25y+22y−110=0
⇒ y2(y−5)+5y(y−5)+22(y−5)=0
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