if x³-3x²+4x+c is exactly divisible by (x-1) then c is
Answers
Answered by
1
Answer:
x- 1 ... x33 jfyiohfx
Step-by-step explanation:
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Answered by
1
Answer:
x-1=0
x=1
therefore
x^3-3x^2+4x+c=0
1-3+4+c=0
2+c=0
c=-2
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