If x3 + 3x2 + 9x = 1, then the value of x3 + 3/x
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Step-by-step explanation:
There is, however, a local minimum.
y=(x+1)3−12(x+1)+12
This has a local maximum for some x<−1 and a local minimum for some x>−1 .
We can pin the values down more precisely.
y′=3(x+1)2−12
with stationary points where y′=0 , or 3(x+1)2=12 , or (x+1)=±2 ; it's easy to verify that x=−3 is a local maximum and x=1 is a local minimum. For x=1 , y=−4 .
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(((x3) - 3x2) - 9x) - 1 = 0
:
Checking for a perfect cube
2.1 x3-3x2-9x-1 is not a perfect cube
Trying to factor by pulling out :
2.2 Factoring: x3-3x2-9x-1
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: -9x-1
Group 2: -3x2+x3
Pull out from each group separately :
Group 1: (9x+1) • (-1)
Group 2: (x-3) • (x2)
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