if x3 + 3x3 + 3x + 1 is divided by (x + 1) then the remainder is
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P(x) = x^3 + 3x^2 + 3x + 1
=> P( - 1) = (-1)^3 + 3(-1)^2 + 3(-1)+ 1
=> P(-1) = - 1 + 3 - 3 + 1
=> Remainder = 0
=> P( - 1) = (-1)^3 + 3(-1)^2 + 3(-1)+ 1
=> P(-1) = - 1 + 3 - 3 + 1
=> Remainder = 0
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