Question

if x³+3x³-ax +3 exactly divisible by x-2 then a is ​

Answer 1

Step-by-step explanation:

x^3+3x^3-ax+3

4x^3-ax+3 divisible by x-2 , then the quotients became then factorise the quotients then

value of a get

Answer 2

Step-by-step explanation:

Given polynomial p(x)=x³+3x²-ax +3

Given divisor =x-2

If x-2 exactly divides the given polynomial then

It is a factor

if it is a factor then p(2)=0 by factor theorem

p(2)=2³+3(2)²-a(2)+3=0

=>8+12-2a+3=0

=>-2a+23=0

=>2a=23

=>a=23/2

The value of a=23/2

or if you gave x³+3x³-ax +3

=>4x³-ax+3

then p(2)=4(2)³-a(2)+3=0

=>32-2a+3=0

=>35-2a=0

=>2a=35

=>a=35/2