Question

If x3 – 6x2 + 11x - 6 = 0 then find the value of (3x - 4)
(a) (1.2.3)
(b) (-1, 2,5)
(c) (-1,3,5)
(d) (2.3,5)
Pls ans

Answer 1

Answer:

Since (x+1) is a factor of given cubic equation.

∴ it will completely divide the given equation.

Now, (x

3

+6x

2

+11x+6)=(x

2

+5x+6)(x+1)

=(x+2)(x+3)(x+1)

∴ zeros of (x+1)(x+2)(x+3)=0 are

x+1=0⇒x=−1

x+2=0⇒x=−2

x+3=0⇒x=−3