If x3 + 6x2 + 11x + k has an element (x + 3), then k = _
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x+3=0
x= -3
(-3)3 + 6(-3)2 + 11(-3) + k = 0
-27 + 54 + -33 + k = 0
27 -33 +k = 0
-6 + k = 0
k = 6
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