Question

if x³+6x²+4x+k is exactely divisible by (x+2) then k=​

Answer 1

Answer:

let P(x) = x^3+6x^2+4x+k

IF (x+2) is the factor of p(x) then x+2=0

x = -2

by remainder theorem P(-2) = 0

(-2)^3+6(-2)^2+4(-2)+k = 0

-8+6(4)-8+k = 0

-8+24-8+k = 0

8+k = 0

k = -8

Step-by-step explanation:

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Answer 2

Answer:

REMAINDER THEOREM AND POLYNOMIALS.