If x³-6x²+6x+9 is completely divisible by x-3 find oher zeroes
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(x²-3x-3
(x-3)√(x³-6x²+6x+9)
x³-3x²
-3x²+6x+9
-3x²+9x
-3x+9
-3x+9
0
then the remainder is zero
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