Question

If x³ - 6x²+6x+k is completly divisible by x-3 , find the value of k​

Answer 1

Answer:

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Answer 2

Answer:

Since p(x) divisible by x-3

Then 3 is one of its zero

P(3)=3^3 - 6*3^2 +6*3+k=0

27-54+18 +k =0

45-54 +k=0

- 9+k = 0

K = 9

Hence the value of k is 9

Step-by-step explanation:

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