Question

if x³-6x²+ax+b is exactly divisible by x²-x-2,then a,b=?​

Answer 1

Answer:

ᕼOᑭᗴ IT ᗯIᒪᒪ ᕼᗴᒪᑭ ᑌ ᗪᗴ.ᗩᖇ

Answer 2

Answer:

$x^{2} -3x+2= ( x-1 ) ( x-2 )$

if f (x) =

${x}^{2} - {6}^{2} + ax + b \:$

is divisible by

${x}^{2} - 3x + 2$

, then it should be divisible by its factors X - 1 and X -2.

f(1) = 0 and f(2) = 0

f(1) = 0 a+ b = 5 ------- 1

f(2) = 0 2a+ b = 16 ------- 2

from( 1 )and (2) , we get a= 11 , b = - 6