If x3
– 7x2 + kx + 15 is exactly divisible by (x – 3), then find the value of k
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Answer:
k = 7
Step-by-step explanation:
If x^3 - 7x^2 + kx + 15 is divisible by x -3
then x-3 is a factor of p (x).
so ,using remainder theorem
x-3 = 0
x = 3
Substituting value of x in p(x)-
3^3 - 7(3)^2 + k (3) + 15 = 0
27 - 63 + 3k + 15 = 0
-21 + 3k =0
3k = 21
k = 21/3
k = 7
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