If x3 + ax2 – bx + 10 is divisible by x2 – 3x + 2, find the values of a and b.
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Step-by-step explanation:
Eq. is x³+ax²-bx+10 and have to check whether it is divisible by x²-3x+2?
First, solve this quadratic eq. =x²-3x+2
by equating this, we have two roots (x)=2 and 1
Put these roots one by one on your eq. =x³+ax²-bx+10
put x=2 in eq.
8+4a-2b+10=0
4a-2b+18=0
4a-2b=-18...................................eq.(1)
put x=1, in eq
1+a-b+10=0
a-b+11=0
a-b=-11............................................eq.(2)
Now equate eq. (1)&(2)
4a-2b=-18
a-b=-11
{we have to make either a or b equal}
4a-2b=-18
2a-2b=-22 (this eq. multiplied with 2 so, that can cancel either a or b,and
here b will cancel)
2a =4
a=2
put this a in any eq. either in 1 or in 2
b=13
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