Question

if x³+ax³-bx+10 is divisible by x²-3x+2, find the values of a and b​

Answer 1

Answer:

hi

Step-by-step explanation:

x^2-3x+2= x^2-x-3x+2= x(x-1)

Answer 2

Step-by-step explanation:

${x}^{2} - 3x + 2 = 0 \\ {x}^{2} - (2 + 1)x + 2 = 0 \\ {x}^{2} - 2x - x + 2 = 0 \\ x(x - 2) - 1(x - 2) = 0 \\ (x - 2)(x - 1) = 0 \\ x = 2 \: and \: x = 1 \\ \\ so \: we \: put \: these \: values \\ {x}^{3} + a {x}^{3} - bx + 10 \\ first \: x = 2 \\ (2) {}^{3} + a(2) {}^{3} - b(2) + 10 = 0 \\ 8 + 8a - 2b + 10 = 0 \\ 8a - 2b + 18 = 0 = = = (1)\\ \\ x = 1 \\ (1) {}^{3} + a(1) {}^{3} - b(1) + 10 = 0 \\ 1 + a - b + 10 = 0 \\ a - b + 11 = 0 = = = (2)\\ solving \: (1) \: and \: (2) \\ b = \frac{70}{6} = \frac{35}{3} \\ a = \frac{2}{3}$