Question

If x3+mx2-x+6 has (x-2) as a factor and leaves a remainder ‘n’ when divided by (x-3) , find the value of m and n .

Answer 1

here is ur answer...

Answer 2

Hey mate......

here's Ur answer.......

f (2) = (2)3 + m(2)2 - 2+6

0 = 8 + 4m - 2 + 6

4m = -12

m = -3.................

f(3) = (3)3 + m(3)2 - 2 + 6

n = 27 + 9m + 4

n = 31+ 9(-3)

n = 31 - 27

n = 4
.....

Hope it Helps.....

Be brainly