Question

if x³+x²-ax+b is divisible by x²-x what are the values of a and b​

Answer 1

Answer:

x² - x = x(x-1)

Its roots are 0, 1

Let p(x) = x³ + x² -ax + b

Remainder must be 0 upon division by x² - x

We take the roots of the divisor and put it in place of x

So p(0) = 0 + 0 - 0 +b = 0

=> b = 0

So p(1) = 1 + 1 - a + b = 0

=> b - a + 2 = 0

=> 0 - a + 2 = 0

=> a = 2

Hence a = 2 and b = 0

HOPE THIS HELPS...