if x³+ x² -ax +b is divisible by (x²-x), write the values of a and b
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Step-by-step explanation:
x² - x = 0
x(x - 1) = 0
x = 0 , 1
Firstly (0)³ + (0)² - a(0) + b = 0
0 + 0 - 0 + b = 0
b = 0
Now , (1)³ + (1)² - a(1) + b = 0
1 + 1 - a + b = 0
2 = a - b
a = b + 2
a = 0 + 2
a = 2
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