Math, asked by Durgesh1029, 11 months ago

If x³+x²+x+1=0 then values of x??

Answers

Answered by saivivek16
2

Step-by-step explanation:

Aloha !

x³+x²+x+1=0

x^6+1=0

x^6=-1

x=(-1)^6

x=1

Thank you

Answered by Sudhir1188
10

ANSWER:

x= 1

GIVEN:

 \implies \: x {}^{3}  + x {}^{2}  + x + 1 = 0

TO FIND:

value of x

SOLUTION:

 \implies \: x {}^{3}  + x {}^{2}  + x + 1 = 0 \:  \\  \implies (x {}^{3}  + x {}^{2} ) + (x + 1) = 0 \:  \\  \implies \: x {}^{2} (x + 1) + (x + 1) = 0 \\  \implies \: (x {}^{2}  + 1)(x + 1) = 0 \\  \\ when \: (x {}^{2}  + 1) = 0 \\  \implies \: x {}^{2}  = ( - 1) \\  \implies x =  \sqrt{( - 1)}  \\ \:  \:  \:  \:  \:  \:  \:  \:  imaginary \: roots

When ;. (x-1)= 0

x= 1

Value of x= 1

NOTE:

  • By doing factorisation we can find the value of x
  • we first have to arrange in a proper order before doing factorisation.
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