If x3 + y2 = 4xy(x + y). Then log(x + y)3
(1) logx + logy + log(x + y) - log7
(2) logx - logy + log(x + y) + log7
(3) logx + logy + log(x - y) + log7
(4) logx + logy + log(x + y) + log7
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Answer:
) logx + logy + log(x - y) + log7
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