If x³ - y³ = 26 and x⁴ -y⁴ = 20(x+y) find the values of x and y .
Answers
Answered by
0
Step-by-step explanation:
Let x²-3x = y.
Then, y² - 8y - 20
= y² - 10y + 2y - 20
= y (y-10) + 2 (y-10)
= (y-10) (y+2)
= (x²-3x-10) (x²-3x+2) [Putting the value]
= (x²-5x+2x-10) (x²-2x-x+2)
= [x(x-5)+2(x-5)] [x(x-2)-1(x-2)]
= (x-5) (x+2) (x-2) (x-1) [ANSWER]
Answered by
2
Answer:
Step-by-step explanation:
Let x²-3x = y.
Then, y² - 8y - 20
= y² - 10y + 2y - 20
= y (y-10) + 2 (y-10)
= (y-10) (y+2)
= (x²-3x-10) (x²-3x+2) [Putting the value]
= (x²-5x+2x-10) (x²-2x-x+2)
= [x(x-5)+2(x-5)] [x(x-2)-1(x-2)]
= (x-5) (x+2) (x-2) (x-1) [ANSWER]
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