If x³-y³=37 and x²+y²=25, find x and y. Need solution
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ambar21
ambar21 Virtuoso
(x+y)=√(x+y)^2
=√(x^2+y^2+2xy)
=√(37+12)
=√49
x+y=7
(x-y)=√(x-y) ^2
=√(x^2+y^2-2xy)
=√(37-12)
=√25
x-y=25
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Answer:
x³-y³-3x²y-3xy²=37. x²+y²=25
x+y=√25 x³-y³-3xy(x+y)=37. x+y=5
x³-y³-3xy(5)=37. cubing both side
x³-y³-15xy=37. x³+y³=5³
x³+y³=125
SORRY THIS SUM IS SO DIFFICULT FOR ME...
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