if x⁴+1/x⁴ is 194.find the value of x³+1/x³.
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Hi ,
****************************************
We know the algebraic identity ,
a² + b² + 2ab = ( a + b )²
**************************************
Now ,
x⁴ + 1/x⁴ = 194 ( given )---( 1 )
( x² )² + ( 1/x² )² + 2 × x² + 1/x² = 194 + 2
( x ² + 1/x² )² = 196
( x² + 1/x² )² = ( 14 )²
x² + 1/x² = 14 ---( 2 )
x² + 1/x² + 2 = 14 + 2
( x + 1/x )² = 16
( x + 1/x )² = 4²
x + 1/x = 4 ----( 3 )
Now ,
*************************************
We know the algebraic identity ,
a³ + b³ + 3ab( a + b ) = ( a + b )³
Or
a³ + b³ = ( a + b )³ - 3ab( a + b )
*****************"*******************
Now ,
x³ + 1/x³ = ( x + 1/x )³ - 3 ( x + 1/x )
= 4³ - 3 × 4
= 64 - 12
= 52
I hope this helps you.
: )
****************************************
We know the algebraic identity ,
a² + b² + 2ab = ( a + b )²
**************************************
Now ,
x⁴ + 1/x⁴ = 194 ( given )---( 1 )
( x² )² + ( 1/x² )² + 2 × x² + 1/x² = 194 + 2
( x ² + 1/x² )² = 196
( x² + 1/x² )² = ( 14 )²
x² + 1/x² = 14 ---( 2 )
x² + 1/x² + 2 = 14 + 2
( x + 1/x )² = 16
( x + 1/x )² = 4²
x + 1/x = 4 ----( 3 )
Now ,
*************************************
We know the algebraic identity ,
a³ + b³ + 3ab( a + b ) = ( a + b )³
Or
a³ + b³ = ( a + b )³ - 3ab( a + b )
*****************"*******************
Now ,
x³ + 1/x³ = ( x + 1/x )³ - 3 ( x + 1/x )
= 4³ - 3 × 4
= 64 - 12
= 52
I hope this helps you.
: )
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