Math, asked by Anuragsingh6003, 10 months ago

If x4-16x3+86x2-176x+105=0 then find s1,s2,s3,s4

Answers

Answered by tanejakca
5
S1=-b/a =16
S2=c/a =86
S3=-d/a=176
S4=e/a=105
Answered by pavanasrigayathri
0

Answer:

16,86,176,105

Step-by-step explanation:

x^4-16x^3+86x^2-176x+105=0  

from x^4+b/a x^3+c/a x^2+d/a x+e/a  we get s1= -b/a-- s2= c/a-- s3= -d/a and s4= e/a.

now from the given equation, a= 1, b= -16,c=86,d= -176 and e= 105.

s1=16

s2=86

s3=176

s4=105

Similar questions