Question

. If x4 + x3 + 8x2 + ax + b is divisible by
x2 + 1, then the values of a and b are
(a) a = -1, b = 7 (b) a = 1, b = -7
(c) a = 1, b = 7
(d) a = -1, b = -7​

Answer 1

Answer:

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Answer 2

Answer:

Option c

Step-by-step explanation:

if x4+x3+8x2+ax+b is divisible by x2+1 , then the remainder should be equal to zero. Thus, we find that the values of a and b so that x4+x3+8x2+ax+b becomes divisible by x2+1 is a=1 and b=7