if (x⁶+1)/x³=3
then find out (x²+1)/x
its urgent
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X^6 + 1 = 3x^3
Let x^3 be a
a^2 - 3a + 1 = 0
a = ( 3 + √5/2 ) or ( 3 - √5/2 )
X = ( 3+√5/2 ) ^ 1/3 or (3-√5/2) ^ 1/3
(X^2 +1)/x = ((( 3+√5/2 )^2/3) + 1) / ((3+√5/2)^1/3) or (((3-5√2)^2/3)+1) / ((3-√5/2)^1/3)
Let x^3 be a
a^2 - 3a + 1 = 0
a = ( 3 + √5/2 ) or ( 3 - √5/2 )
X = ( 3+√5/2 ) ^ 1/3 or (3-√5/2) ^ 1/3
(X^2 +1)/x = ((( 3+√5/2 )^2/3) + 1) / ((3+√5/2)^1/3) or (((3-5√2)^2/3)+1) / ((3-√5/2)^1/3)
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