Question

If xn + yn is completely divisible by (x + y), then which of the following can be the value of "n"?​

Answer 1

Let p(x) = x^n+y^n it’s divisible by x+y so zero of p(x) = -y putting it in p(x) as p(y)
P(y) = (-y)^n +y^n (if n odd ,-yn = -yn n even,-yn = yn)
So for only odd values of n ,p(y) =0
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