Math, asked by sumit7285, 5 months ago

If xsecA=1-ytanA and x^2sec^2 A=5+y^2tan^2A then
a)x^2=9y^2/y^2+4
b)x^2=4y^2/9-y^2
c)y^2=4x^2/9+x^2
d)y^2=9x^2/x^2+4​
Solve this.​

Answers

Answered by Madankumar808103
0

Answer:

If xsecA=1-ytanA and x^2sec^2 A=5+y^2tan^2A then

a)x^2=9y^2/y^2+4

b)x^2=4y^2/9-y^2

c)y^2=4x^2/9+x^2

d)y^2=9x^2/x^2+4

Solve this.

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