Question

if xsin³A + ycos³A = sinAcosA & xsinA - ycosA=0, then show us, x²+y²=1​

Answer 1

Answer:

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Answer 2

we have X sin^3A+ ycos^3A= sin A. cosA

= (X sin A). sin^2A+ (ycos A).cos^2A= sinA.cosA

=X sinA.(sin^2A)+(X sin A). cos^2A=sinA.cosA

[since X sinA=ycosA]

=X sin A(sin^2A+cos^2)=sinA.cosA

=X sin A=sinA.cosA==X = cos A----------equation1

Now,X sinA=y cosA

=sinA.cosA=y cosA

y=sinA---------equation2

From 1and2

Hence,x^2+y^2=cos^2A+sin^2A=1