if xsin³A+ycos³A=sinAcosA and xsinA=ycosA prove that x²+y²=1
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Hey, that came in our school's mock test. Here what we'll do is -

[tex]ycosA(sin^{2}A + cos^{2}A) = sinAcosA [/tex]

From second condition,



[tex]ycosA(sin^{2}A + cos^{2}A) = sinAcosA [/tex]
From second condition,
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