Question

if xsq. +4ysq.=17 and and xy=2, then find the value of x+2y​

Answer 1

♥♥♥hello mate ♥♥♥♥

follow me

Answer 2

Hey Piyush ,

the answer is 5

${x}^{2} + 4{y}^{2} = 17 \\ add \: 4xy \: on \: both \: side \\ {(x)}^{2} + {(2y)}^{2} + 2 \times x \times 2y = 17 + 4xy$

${(x + 2y)}^{2} = 17 + (4) \times (2) \\ {(x + 2y)}^{2} = 25 \\ (x + 2y) = \sqrt{25} \\ x + 2y = 5$

Hope it helps