if xsquare+1/xsquare=3 find the value of x-1/x
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Given
x^2 + 1/x^2 = 3
To find
x - 1/x = ?
Solution
( x - 1/x )^2 = ( x )^2 + ( 1/x )^2 - 2 ( x ) ( 1/x )
( x - 1/x )^2 = x^2 + 1/x^2 - 2
( x - 1/x )^2 = 3 -2
( x - 1/x )^2 = 1
taking square root of both the sides we get
( x - 1/x ) = 1
x^2 + 1/x^2 = 3
To find
x - 1/x = ?
Solution
( x - 1/x )^2 = ( x )^2 + ( 1/x )^2 - 2 ( x ) ( 1/x )
( x - 1/x )^2 = x^2 + 1/x^2 - 2
( x - 1/x )^2 = 3 -2
( x - 1/x )^2 = 1
taking square root of both the sides we get
( x - 1/x ) = 1
ronak50:
thanks a lot
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