if xsquare + 1by x square = 5 find xcube + 1by xcube
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o don't know bro sorry
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GIVEN X²+1 / X² = 5
==> A²+B² = (A+B)²-2XY
==> (X+1/X)²-2.X.1/X = 5
==> (X+1/X)²-2 = 5
==> (X+1/X)² = 7
==> X+1/X = √7
S0, LET TAKE (A+B)³ FORMULA
==> (A)³+(B)³+3AB(A+B)
==> (X)³+(1/X)³+3.X.1/X(X+1/X)
==> X³+(1/X)³ + 3(√7)
=> X³+(1/X)³ = -3√7
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