If xsquare+ysquare=38xy then show that 2log(x+
y)=2log6+logx+logy
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X2 + y2 = 38xy
(X+y)2 = 38xy + 2xy = 40xy
X+y = root (40xy)
2 log (x+y) = 2 log (root 40xy)
It’s more complicated from here
I’m sorry but I could only solve till here
(X+y)2 = 38xy + 2xy = 40xy
X+y = root (40xy)
2 log (x+y) = 2 log (root 40xy)
It’s more complicated from here
I’m sorry but I could only solve till here
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