if xsquare + ysquare then prove that 2log(x-y)=logx+logy+2log5
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x²+y²=25xy
adding 2xy on both sides
x²+y²+2xy=27xy
[x+y]²=27xy
taking log on both sides
log[x+y]²=log27xy
2log[x+y]=log3³+log x+log y
2 log[x+y]=3log3+logx+logy
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