Question

If xx cube -13x square +17x+12, find f(-1/3)

Answer 1

$eq {}^{n} = > \: x {}^{3} - 13x {}^{2} + 17x + 12$

FACTOR = -1/3

So,

$= > ( \frac{ - 1}{3}) {}^{3} - 13( \frac{ - 1}{3} ) {}^{2} + 17 (\frac{ - 1}{3} ) + 12$

$= > \: \frac{ - 1}{27} - \frac{13}{9} - \frac{ 17}{3} - + 12$

$= > \frac{131}{27}$

HOPE ITS HELPFUL....:-)