If Xx.Yy.Zz=Xy.Yz.Zx=Xz.Yx.Zysuch that x y z are positive integers greater than 1 then which of the following cannot be true for any of the possible value of x y z??? (i)xyz=27 (ii)xyz=1728 (iii)x+y+z=32 (iv)x+y+z=12
Answers
Answered by
0
By solving the equation, the result comes:-
x=y=z
So (iii) x + y + z = 32 is not possible.
Because in place of y & z , we can substitute x
So if
x + y + z = 32
=> x + x + x = 32
=> 3x = 32
=> x = 32/3
As x is not a whole number in this case this is not possible
HOPE IT HELPED
PLEASE MARK IT AS THE BRAINLIEST ANSWER
x=y=z
So (iii) x + y + z = 32 is not possible.
Because in place of y & z , we can substitute x
So if
x + y + z = 32
=> x + x + x = 32
=> 3x = 32
=> x = 32/3
As x is not a whole number in this case this is not possible
HOPE IT HELPED
PLEASE MARK IT AS THE BRAINLIEST ANSWER
Similar questions