Math, asked by RaviRavindersingh, 1 year ago

if xy=180,and hcf(x,y)=5,find LCM x, y​

Answers

Answered by Anonymous
39
  • xy = 180

  • HCF = 5

___________ [GIVEN]

• We have to find LCM

______________________________

We know that..

Product of two numbers = HCF × LCM

Here xy is product whose value is 180 and HCF is 5. By putting these values in above formula, we got the value of LCM.

• Let LCM be M

=> 180 = 5 × M

=> 5M = 180

=> M = 180/5

=> M = 36

______________________________

So.. \huge{\bold{LCM\: is \:36}}

__________ \bold{[ANSWER]}

______________________________

✡ Product of two numbers = LCM × HCF

From above calculations and according to question.. we have Product of two numbers is 180, HCF is 5 and LCM is 36

=> 180 = 5 × 36

=> 180 = 180

_______ [HENCE VERIFIED]

______________________________

Answered by itzdevilqeen
13

\large \:xy \:= \:180

\large \:HCF \:= \:5

___________ \large \:[GIVEN]

• We have to find LCM

______________________________

We know that..

Product of two numbers = \large \:HCF \:× \:LCM

Here xy is product whose value is 180 and HCF is 5. By putting these values in above formula, we got the value of LCM.

• Let LCM be M

=> 180 = 5 × M

=> 5M = 180

=> M = 180/5

=> M = 36

______________________________

So.. \huge{\bold{LCM\: is \:36}}

__________ \bold{[ANSWER]}

______________________________

✡ Product of two numbers = LCM × HCF

From above calculations and according to question.. we have Product of two numbers is 180, HCF is 5 and LCM is 36

=> 180 = 5 × 36

=> 180 = 180

_______ [HENCE VERIFIED]

______________________________

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