If xy - 2x - 3y +6 = 0 are pair of normals to a circle 5 which Intersects the circle x2 + y2 - 2x - 2y - 2 = 0 orthogonally, then radius
of the circle S is
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Answer:
⇒x=−3
and y=
2
−x
=
2
3
⇒(−3,
2
3
) is the centre of required circle.
(∵x(x−4)+y(y−3)=0 is the diametric form of the circle. Hence, (0,0) and (4,3) are the diametric end points.)
⇒ Centre →(
2
0+4
,
2
0+3
)→(2,
2
3
)
radius =
2
1
(
16+9
)
=
2
5
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