If xy = -30 and x2 + y2 = 61, then find the value of (x + y).
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Correct Question :-
If xy = -30 and x² + y² = 61, then find the value of x + y.
Answer :-
x + y = 1
Solution :-
We know that
(x + y)² = x² + y² + 2xy
Here
• xy = - 30
• x² + y² = 61
By substituting the values
⇒ (x + y)² = 61 + 2(-30)
⇒ (x + y)² = 61 - 60
⇒ (x + y)² = 1
⇒ x + y = √1
⇒ x + y = 1
Therefore the value of x + y is 1.
Verification :-
(x + y)² = x² + y² + 2xy
⇒ (1)² = 61 + 2(-30)
⇒ 1 = 61 - 60
⇒ 1 = 1
Identity used :-
• (x + y)² = x² + y² + 2xy
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