Math, asked by CrashsomeCastles, 4 months ago

If XY=32, XZ=28, JQ=12, and the radius of the circumscribed circle of (triangle)XYZ is 20, find QK.

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Answered by agrimkingrevenge

0

Answer:

MX=MY,XY=XZ and MN∥XZ

⇒∠XZY=∠MNY⇒∠MYN=∠MNY

⇒MN=MY also MY=MX(∵∠y=∠z)

⇒MN=MY=MX

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