Math, asked by CrashsomeCastles, 4 months ago

If XY=32​, XZ=28​, JQ=12​, and the radius of the circumscribed circle of (triangle)XYZ is ​20, find QK.

Answers

Answered by farhaanaarif84
1

Answer:

In a circle, the line joining the center of the circle to the mid-point of a chord is perpendicular to the chord.

Given that

D

,

E

,

F

are the midpoint of chords

A

B

,

A

C

,

and

B

C

, and

O

D

,

O

E

,

and

O

F

are perpendicular to chords

A

B

,

A

C

,

and

B

C

, respectively,

point

O

is the center of the circumscribed circle.

In other words, the three perpendicular bisectors of

A

B

,

A

C

,

and

B

C

meet at point O,

point

O

is the center of the circumscribed circle.

O

A

,

O

B

=

the radius of the circle

O

A

=

O

B

Given that

O

A

=

5

x

8

,

and

O

B

=

3

x

,

5

x

8

=

3

x

x

=

4

O

A

=

O

B

=

3

x

=

3

4

=

12

Hence, the radius of the circumcircle

=

12

Answer link

Answered by eavalejandro22
3

Answer:

14.3

Step-by-step explanation:

just did the question

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