Question

if xy=4 and xy^2=16, what is the value of x?

Answer 1

Let’s take x = 2 nd y=2
1st condition = 2*2= 4
2nd condition = xy^2 = 16
= 2*2^2 = 4^2 = 16 satisfied so x= 2

Answer 2

as xy= 4
y = 4/x
put it in (xy)^2
and find the value of x