if xy=4 and xy^2=16, what is the value of x?
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Answered by
6
Let’s take x = 2 nd y=2
1st condition = 2*2= 4
2nd condition = xy^2 = 16
= 2*2^2 = 4^2 = 16 satisfied so x= 2
1st condition = 2*2= 4
2nd condition = xy^2 = 16
= 2*2^2 = 4^2 = 16 satisfied so x= 2
Answered by
0
as xy= 4
y = 4/x
put it in (xy)^2
and find the value of x
y = 4/x
put it in (xy)^2
and find the value of x
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