Question

If xy = 56 and x2+ y2= 113, then what will be the value of (x + y)?

A) 29 B) 21 C) 36 D) 15

Answer 1

Answer:

D) 15

Step-by-step explanation:

x and y are the factors of 56. When we try each of them, we get x and y = 7 and 8. So, 7+8=15. So, 5 is the right answer, which is Option D.

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Answer 2

$\mathbb\purple{♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡}$

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$

$\mathbb\</em></strong><strong><em>green</em></strong><strong><em>{</em></strong><strong><em>=>X^2+y^2=(x+y)^2-2xy</em></strong><strong><em>}$

$\mathbb\</em></strong><strong><em>pink</em></strong><strong><em>{</em></strong><strong><em>=>113=(x+y)^2-2(56)</em></strong><strong><em>}$

$\mathbb\red{</em></strong><strong><em>=>113=(x+y)^2-112</em></strong><strong><em>}$

$\mathbb\</em></strong><strong><em>blue</em></strong><strong><em>{</em></strong><strong><em>=>(x+y)^2=113+112</em></strong><strong><em>}$

$\mathbb\</em></strong><strong><em>orange</em></strong><strong><em>{</em></strong><strong><em>=>(x+y)^2=225</em></strong><strong><em>}$

$\mathbb\</em></strong><strong><em>green</em></strong><strong><em>{</em></strong><strong><em>=>(x+y)^2=15^2</em></strong><strong><em>}$

$\mathbb\red{</em></strong><strong><em>=>x+y=15</em></strong><strong><em>}$

$\mathbb\</em></strong><strong><em>purple</em></strong><strong><em>{</em></strong><strong><em>So,</em></strong><strong><em>option</em></strong><strong><em>\</em></strong><strong><em>:</em></strong><strong><em>D) 15</em></strong><strong><em>}$

$\</em></strong><strong><em>mathbb</em></strong><strong><em>\</em></strong><strong><em>pink</em></strong><strong><em>{</em></strong><strong><em>16THANKS</em></strong><strong><em>+</em></strong><strong><em>FOLLOW</em></strong><strong><em>=</em></strong><strong><em>INBOX</em></strong><strong><em>}$

$\</em></strong><strong><em>mathbb</em></strong><strong><em>\</em></strong><strong><em>green</em></strong><strong><em>{</em></strong><strong><em>♡</em></strong><strong><em>♡</em></strong><strong><em>♡</em></strong><strong><em>♡</em></strong><strong><em>♡</em></strong><strong><em>♡</em></strong><strong><em>♡</em></strong><strong><em>♡</em></strong><strong><em>♡</em></strong><strong><em>♡</em></strong><strong><em>♡</em></strong><strong><em>♡</em></strong><strong><em>♡</em></strong><strong><em>♡</em></strong><strong><em>♡</em></strong><strong><em>♡</em></strong><strong><em>}$