If xy = 6 and 8xcube +27ycube =793 prove that 2x+3y=13
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we have xy=6
and 8x^3 +27y^3= 793
( 2x)^3 +(3y)^3= 793
(a+b)^3= a^3+b^3+3a^2b+3ab^2
= 793 -3(2x)(3y)(2x+3y)
793-18(xy)(2x+3y)
18(6)(2x+3y)= 793
2x+3y=. 793/108
BRO I DON'T NO WHY IT IS ISN'T PROVE PLS CHECK QUESTION
and 8x^3 +27y^3= 793
( 2x)^3 +(3y)^3= 793
(a+b)^3= a^3+b^3+3a^2b+3ab^2
= 793 -3(2x)(3y)(2x+3y)
793-18(xy)(2x+3y)
18(6)(2x+3y)= 793
2x+3y=. 793/108
BRO I DON'T NO WHY IT IS ISN'T PROVE PLS CHECK QUESTION
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