Math, asked by nsiou8686, 1 year ago

If xy = 6 and 8xcube +27ycube =793 prove that 2x+3y=13

Answers

Answered by Anonymous
2
we have xy=6
and 8x^3 +27y^3= 793


( 2x)^3 +(3y)^3= 793

(a+b)^3= a^3+b^3+3a^2b+3ab^2

= 793 -3(2x)(3y)(2x+3y)
793-18(xy)(2x+3y)
18(6)(2x+3y)= 793

2x+3y=. 793/108



BRO I DON'T NO WHY IT IS ISN'T PROVE PLS CHECK QUESTION
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