Question

If xy=a+2÷3 and y/x=1/3,then find the value of x^2+y^2÷x^2-y^2​

Answer 1

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Answer:

6a+4/3a+2

Step-by-step explanation:

xy=a+2/3 y/x=1/3

x=3y. So put the x value

3y×y=a+2/3

y^2 =3a+2/3

And x^2=3a+2

So put the value of x^2 and y^2

3a+2+3a+2/3/3a+2-(3a+2)/3

9a+6+3a+2/9a+6-3a-2

6a+4/3a+2 ans.