If xy=a+2÷3 and y/x=1/3,then find the value of x^2+y^2÷x^2-y^2
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Answer:
6a+4/3a+2
Step-by-step explanation:
xy=a+2/3 y/x=1/3
x=3y. So put the x value
3y×y=a+2/3
y^2 =3a+2/3
And x^2=3a+2
So put the value of x^2 and y^2
3a+2+3a+2/3/3a+2-(3a+2)/3
9a+6+3a+2/9a+6-3a-2
6a+4/3a+2 ans.
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