Question

If xy =x power x then I / logx(y) + 1 is

Answer 1

Answer:

if xy =x power =1 log ×yis the answer

Answer 2

Answer:

Here we should find the value of $\frac{1}{\log xy}+1$ using given data.

Final Answer:  $\frac{1}{\log xy}+1= \frac{1+x\log x}{x\log x}$

Step-by-step explanation:

Question: $xy =x ^ x$ then $\frac{1}{\log xy}+1$ =?

From the given question,

• We consider $xy =x ^ x$ is the first equation using this equation we can find the value of $\frac{1}{\log xy}+1$ .

                         $xy =x ^ x$  --------------(1)

• Now Taking log on both sids.That is,

                   $\log xy=\log x^x$

• Already we know logarithm formula for the power is, $\log a^b=b\log a$
• Apply this logarithm formula in the above equation. That is,

                   $\log xy=x \log x$ -------------(2)

• Now apply the equation(2) in the given question.

              $\frac{1}{\log xy}+1= \frac{1}{x\log x}+1$

• Take the L.C.M on the Right Hand Side. So that,

              $\frac{1}{\log xy}+1= \frac{1+x\log x}{x\log x}$

Final Answer:  $\frac{1}{\log xy}+1= \frac{1+x\log x}{x\log x}$