Question

if xy+x+y=5,yz+y+x=11,zx+z+x=7 then what is the value of x:y:z​

Answer 1

Answer:

What do you read ? or Tum kon kokhsha me porti hey

Answer 2

Answer:

Step-by-step explanation:

xy+x+y=5

xy+x+y+1=6

x(y+1)+1(y+1)=6

(x+1)(y+1)=6

Similarly (y+1)(z+1)=12

And (x+1)(z+1)=8

Multiplying we get,

(x+1)(y+1)(z+1)= sqrt(6×8×12) = 24

Therefore (x+1)=2, x=1

(y+1)=3, y=2

(z+1)=4, z=3

Therefore x:y:z= 1:2:3