Question

if xy(x+y)=m
then x³+y³+3m=m³/x³y³ prove it

Answer 1

using algebraic identity we the proof

Answer 2

if xy(x+y)=m

[xy(x+y)]^3=m^3

x^3×y^3×(x+y)^3=m^3

x^3+y^3+3xy(x+y)=m^3/x^3y^3

${x}^{3} + {y}^{3} + 3m = {m}^{3 } \div {x}^{3} {y}^{y}$

because xy(x+y)=m