If xy.yx = m , m is constant then dy/dx
is equal to
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Step-by-step explanation:
Given If xy . yx = M, where M is constant then dy / dx is equal to
Now x^y x y^x = M (given)
Taking log on both sides we get
So log x^y . y^x = log M
So log x^y + log y^x = log M
So y log x + x log y = log M
Differentiating with respect to x
So y/x + log x dy/dx + x/y dy/dx + log y = 0
So dy/dx (x/y + log x) = - log y – y/x
So dy/dx = - (x log y + y / x) / (x + y log x / y)
Or dy/dx = - y/x (x log y + y / y log x + x)
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